CHAPTER 5 AC PRETEST AND REVIEW204QUESTIONSA. L5 1 mH (0.001 H), f 5 10 kHz B. L5 0.01 mH, f 5 5 MHz ANSWERSA. XL1 5 6.28 3 1033 0.001 5 6.28 ohmsXL2 5 6.28 310 3 1033 0.001 5 62.8 ohmsB. XL1 5 6.28 3 1033 0.01 3 10−35 0.0628 ohms XL2 5 6.28 3 5 3 106 × 0.01 3 10−35 314 ohmsA circuit containing an inductor in series with a resistor functions as a voltage divider, just as a circuit containing a capacitor in series with a resistor does. Again, the relationship between the input and output voltages is not as simple as a resistive divider. The circuit is discussed in Chapter 6.RESONANCE19 Calculations in previous problems demonstrate that capacitive reactance decreases as frequency increases, and that inductive reactance increases as frequency increases. If a capacitor and an inductor are connected in series, there is one frequency at which their reactance values are equal.QUESTIONSA. What is this frequency called? B. What is the formula for calculating this frequency? You can ﬁnd it by setting XL 5 XC and solving for frequency. Book Authorc05V107/04/2012 3:03 PM c05.indd 2047/4/2012 3:04:31 PM